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posted ago by kekistani_prince ago by kekistani_prince +40 / -2

Don't dox me for the love of god please, I have children and I'm just a passionate hobbyist

I made claims. You want the proof, I've got the proof, here's the oscilloscope readings to prove it: https://www.youtube.com/watch?v=bNyyG1ECN2Q&t=195s

That machine currently makes 50 KV sparks.

That machine is pushing milli-amps of current to make those voltages on that resistor. that means that the machine can push that current at 50 KV.

To make a 1 volt drop over a 1 kilo-ohm resistor requires the transfer of 1 milli-amp of current. As you can see in the video: much more than that is made.

If the voltage is drop is 2.5 volts, then the current through the resistor is 2.5 milliamps.

The machine can deliver that at 50,000 volts 50,000 volts * 0.0025 amps = 125 watts

When the machine is perfected, it will make 208 KV and the sparks will have to cross the bars instead of shorting through the insulation.

That drill spins at up to 2700 rpm, it's running on 120 volt, it uses a maximum of 4.6 amps of current. So that drill, at it's maximum output power uses 552 watts. That drill is not being pushed that hard to make what I am already making, I have a 60 watts pump motor that does this just fine other than the fact I need to buy a speed controller so that I don't rip my fittings apart on startup and so that I can stop it from spinning at max speed.

I can't even go over 1200 RPM yet because of balancing issues...

Now obviously, that output is going to need to be rectified and conditioned, but there it is.

It's not even working right yet and the max output is already reaching overunity levels.