So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 208 KV on the current barrel and 216 KV on the new barrel, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test yesterday morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

In order to produce 210 KV like I want to, I'm going to need to either provide an extremely high impedance/resistive load or tune a spark gap.

But yesterday I spun at 1600 rpm and I made a continuous 1 cm spark and with my machines dimension and the engineering parameters, I made 63 watts.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test yesterday morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

In order to produce 210 KV like I want to, I'm going to need to either provide an extremely high impedance/resistive load or tune a spark gap.

But yesterday I spun at 1600 rpm and I made a continuous 1 cm spark and with my machines dimension and the engineering parameters, I made 63 watts.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test this morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

In order to produce 210 KV like I want to, I'm going to need to either provide an extremely high impedance/resistive load or tune a spark gap.

But yesterday I spun at 1600 rpm and I made a continuous 1 cm spark and with my machines dimension and the engineering parameters, I made 63 watts.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test this morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

In order to produce 210 KV like I want to, I'm going to need to either provide an extremely high impedance/resistive load or tune a spark gap.

But today I spun at 1600 rpm and I made a continuous 1 cm spark and with my machines dimension and the engineering parameters, I made 63 watts.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test this morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

In order to produce 210 KV like I want to, I'm going to need to either provide an extremely high impedance/resistive load or tune a spark gap.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test this morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air which is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

In my case for the test this morning, I had a 1 cm gap. In order to arc accross that, the machine needs to match the ionisation potential of the air with is 30 KV/cm.

So my machine matched the required voltage to make the spark, after which point, all of the produced current could flow and then the voltage stabilised because the current flow out of the machine matched the current production of the machine.

The voltage only rises when current production exceeds current draw.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM (according to the engineering department at the federal university of RIo De Janeiro ) where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.

So the maximum voltage these machines make, not the voltage I made in a "does it even work" test, is determined by the distance between the plates on the disk/barrel.

In my case, from anode to neutralizer bar to cathode, the electricity would need to jump across 8 plate gaps.

Because of the distance between plates my machine will only short out internally at 216 KV, so that's the maximum voltage my machine can match to push electrons.

These can also be thought of like voltage matching current supplies to an extent because they will raise their output voltage until the the current flow in the circuit matches what the machine is trying to produce.

This is why they spark so far, stick these in an insulating gas like helium and they produce megavolts because you eliminate interplate sparking.

The amperage these machine produce is given by the formula C = 26.55uA x A x RPM where A is the surface are in square meters that is used to transfer charge in a rotation.

In my case I have 10 mm by 170mm strips (18x180 on the new barrel) and there is 30 of them

So with that surface area the original barrel produces 1.37 uA per rotation.

Since I have that, I can just multiply by my set speed and tell you what amperage the machine will push at what RPM.

The voltage will climb until those amps get pushed out of the machine through the circuit. As long as I don't exceed the internal short circuit voltage.

So I can provide those milliamps at a maximum of that voltage.