op is correct that statistically this is impossible. Even if you only look at the digits in the tripcode, 1, 1, 3, and 6, the probability that every single one of 4 random digits would show up in a tweet which has around 10 (relatively random) digits is pretty low: (1-(1-1/10)^10)^4 = ~0.18 = 18%

Then there are a total of 13 capital letters in the tweet, 3 capitol letters in the trip code (the following calculation will ignore letter frequencies for simplicity): (1-(1-1/26)^13)^3 = ~0.06 = 6%

together .06*.18 = ~1% And this number will continue to shrink the more factors you take into account

These are absolutely not methods for calculating the exact probability of this, but will generally correlate with the actual answer, and should at least make a point. Anyone feel free to correct me if i made any mistakes.

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