Hello everyone,

Since Trump has been indicted again, he will have to prove the frauds during the 2020 election to defend himself, and I am pretty sure he will.

I want to share an analysis I conducted regarding the deviations of bellwether counties in the 2020 presidential election. For context, a bellwether county is a county that has historically voted for the candidate who became the President. There are 19 such counties in the United States.

In the 2020 presidential election, 18 out of these 19 counties voted for the candidate who did not win the election. This is a highly improbable event, and I wanted to calculate the exact probability of this occurrence.

To do this, I used historical data from the presidential elections from 1980 to 2016. Here are the deviations for each electoral cycle from 1980 to 2016:

1980: 1 deviation (source: https://en.wikipedia.org/wiki/1980_United_States_presidential_election)

1984: 1 deviation (source: https://en.wikipedia.org/wiki/1984_United_States_presidential_election)

1988: 2 deviations (source: https://en.wikipedia.org/wiki/1988_United_States_presidential_election)

1992: 6 deviations (source: https://en.wikipedia.org/wiki/1992_United_States_presidential_election)

1996: 1 deviation (source: https://en.wikipedia.org/wiki/1996_United_States_presidential_election)

2000: 1 deviation (source: https://en.wikipedia.org/wiki/2000_United_States_presidential_election)

2004: 3 deviations (source: https://en.wikipedia.org/wiki/2004_United_States_presidential_election)

2008: 1 deviation (source: https://en.wikipedia.org/wiki/2008_United_States_presidential_election)

2012: 1 deviation (source: https://en.wikipedia.org/wiki/2012_United_States_presidential_election)

2016: 3 deviations (source: https://en.wikipedia.org/wiki/2016_United_States_presidential_election)

By adding up the total number of deviations (20) and dividing it by the total number of counties over all cycles (190), we get an average probability of deviation per county per electoral cycle of 0.105.

The probability that 18 out of 19 counties deviate in an electoral cycle is therefore calculated using the formula for the binomial distribution:

P(k; n, p) = C(n, k) * (p^k) * ((1 - p)^(n - k))

where:

P is the probability, C is the binomial coefficient (the number of ways to choose k successes from n trials), p is the probability of success of a trial, k is the number of successes, n is the total number of trials. By replacing n with 19 (the total number of bellwether counties), k with 18 (the number of counties that voted for the losing candidate), and p with 0.105 (the probability of deviation for a bellwether county), we get a probability of about 4.09e-17. The detailed calculation is as follows:

P(18; 19, 0.105) = C(19, 18) * (0.105^18) * ((1 - 0.105)^(19 - 18))

This means that the probability that 18 out of 19 bellwether counties vote for the losing candidate in the 2020 presidential election is one in 24,449,877,506,112,469 (twenty-four quadrillion four hundred forty-nine trillion eight hundred seventy-seven billion five hundred six million one hundred twelve thousand four hundred sixty-nine). To put this in perspective, the probability of winning the Powerball lottery in the United States is 1 in 292,201,338 (two hundred ninety-two million two hundred one thousand three hundred thirty-eight) (source: https://www.powerball.com/powerball-prize-chart). To reach a probability of 4.09e-17, you would have to win the Powerball lottery about twice in a row (2.07).

Share that with your normies friends and family, and if that does not wake them up, it means they just don't want to do so. These are not opinions, testimonies or documents, this is math, hard math.

I invite you to check these calculations for yourself and share your thoughts.