My last post told you all how to get free energy, I showed you the simple device you can make at home to do it: a wimshurst machine.
Since people automatically think you're an idiot when you show this stuff, I'll let chatgpt explain the important sections this time so you can see that even the cabals robot agrees with the science, there will be a video posted alongside, showing the device in question so that the questions make sense:
Q: How many volts is a 6.5 inch spark considering the breakdown voltage of air is 30 kv/cm
A: The breakdown voltage of air is commonly approximated as 30 kilovolts per centimeter (30 kV/cm). This means that when the electric field in the air exceeds 30 kV/cm, the air will ionize and become conductive, allowing a spark to form.
Assuming that the spark in question is a 6.5 inch spark (which is about 16.5 centimeters), we can calculate the minimum voltage required to produce the spark by multiplying the breakdown voltage of air by the distance of the spark:
Minimum voltage = Breakdown voltage x Distance Minimum voltage = 30 kV/cm x 16.5 cm Minimum voltage = 495 kV
Q: If I charge 500 picofarad capacitor to 495 kilovolts, how many watts are available in the capacitor if discharged over 1 second
A: To calculate the amount of energy stored in a capacitor that has been charged to a certain voltage, we can use the following formula:
Energy = 0.5 x C x V^2
where: C = the capacitance of the capacitor, in farads V = the voltage across the capacitor, in volts
In this case, we have a capacitor with a capacitance of 500 picofarads (500 x 10^-12 farads) that has been charged to a voltage of 495 kilovolts (495,000 volts).
Plugging these values into the formula, we get:
Energy = 0.5 x 500 x 10^-12 x (495,000)^2 Energy = 61.31875 joules
So the capacitor stores 61.31875 joules of energy.
If the capacitor is discharged over 1 second, the power delivered by the capacitor can be calculated using the formula:
Power = Energy / Time
where Time is the time over which the capacitor is discharged.
In this case, the time is 1 second, so we have:
Power = 61.31875 joules / 1 second Power = 61.31875 watts
Therefore, if the 500 picofarad capacitor charged to 495 kilovolts is discharged over 1 second, the power available is approximately 61.32 watts
Q: Does a capacitor contain the same amount of energy no matter the drainage speed
A: The amount of energy stored in a capacitor is determined by its capacitance and the voltage across it. Once the capacitor is charged, the energy stored in it is independent of the discharge speed, as long as the capacitor is discharged fully.
In other words, if a capacitor is charged to a certain voltage and then discharged completely, the amount of energy released during the discharge is always the same, regardless of how quickly or slowly the discharge occurs. The discharge speed will only affect the rate at which the energy is released, which determines the power (energy per unit time) delivered by the capacitor.
However, if the capacitor is not discharged fully, the amount of energy released during the partial discharge will be proportional to the amount of charge removed from the capacitor. In this case, the discharge speed will affect the amount of charge removed per unit time, and therefore the amount of energy released per unit time (power).
So, in summary, the amount of energy stored in a capacitor is independent of the discharge speed as long as the capacitor is discharged fully. If the capacitor is not discharged fully, the amount of energy released will be proportional to the amount of charge removed, and the discharge speed will affect the power delivered
Q: If I had a hand crank generator that could easily be turned with one hand to make 61.32 watts, would that be impressive?
A: A hand crank generator that can produce 61.32 watts of power would be considered relatively high output for a human-powered generator. This amount of power would be enough to run small electronics like cell phones, laptops, and LED lights, and could also be used to charge batteries or power other low-power devices.
The ease of use of the generator would depend on a number of factors, including the design of the generator, the efficiency of the generator, and the strength and endurance of the person turning the crank. However, if the generator is designed to be easy to turn with one hand and has a high efficiency, it could be a practical and useful tool for generating power in a variety of situations, such as during power outages, camping trips, or emergency situations.
Overall, a hand crank generator that can produce 61.32 watts of power would be impressive and useful for a variety of applications, especially if it is designed to be easy to use and efficient
Q: What is the highest output hand crank generator you are aware of?
A: There are a few high output hand crank generators available on the market, with some models capable of producing several hundred watts of power. Here are a few examples:
K-Tor Power Box: This is a hand crank generator that can produce up to 120 volts and 20 watts of power. It has a durable construction and can be used to charge a variety of devices, including cell phones, laptops, and small appliances.
Pedal-A-Watt: This is a pedal-powered generator that can also be used as a hand crank generator. It can produce up to 100 watts of power, which is enough to power small appliances or tools.
Freeplay Encore: This is a hand crank generator that can produce up to 10 watts of power, which is enough to charge small electronic devices like cell phones or radios. It has a compact design and can be used for emergency power in the event of a power outage or natural disaster.
So now here's the link to the wimshurst video: https://m.youtube.com/watch?v=3kMQJk8HZZg&t=2505s
He starts playing with it 40 minutes in and the fastest he made sparks was around 1 per second, he usually spins it up to about that speed, then let's go and talks about something while the wheels slow down and the machine continues to throw sparks.
Each of those sparks is worth 61.32 joules, he's making 61.32 watts as an average per second, whith, what looks to me to be, very little effort.
Let me ask you, how hard do you think turning those wheels is?
At 41:43 he lets go of the wheel, if we count the sparks we can count how many watts in sparks the machine produces as it spins down.
I count two full length sparks and then 1 spark that, to me looks to be around 1-2 cm long, so negligible for the last discharge.
Still, that's 122.64 joules as the thing slows down.
That's not very much effeort for it to spin down like that under load.
I built a leg cranked generator a number of years ago from an old exercise bike and a car alternator and an inverter. I used it to demonstrate at fairs how hard it it to keep a 100W incandescent bulb lit compared to compact fluorescents.
It's was very hard to maintain 100W using my device. You had to pedal very hard. It may have been quite a lossy machine. It gave people a good appreciation that you cannot supply many watts with hand cranked power, and to appreciate what power we use in society.
Considering each spark is worth 61.32 joules and he makes one at a frequency of 1 hz at his top speed. It's pretty wild to see him make 60 watts (rounded down to the tens) with one hand like it's nothing and see more sparks fly off as the wheel slows down after he lets go eh?
Blew my mind, I worked on and around heavy industrial generators and motors. When you have a geny on load it doesn't take that long to slow down from the back emf.
When I see the operation of that machine, I see proof of overunity in the sense that it looks to operate with a COP and the energy differential is useful to us, making 60 watts is not easy. Like a heat pump, but instead of creating thermal kinetic energy potentials you can create charge potentials.
I think I see a possible mistake in the calculations. The spark voltage seems reasonable, but the number of joules seems to high, I don't think he's putting in 60W with that cranking and I also think that the discharge lasts for thousandths of a second and not 1 second. maybe his capacitor jars have a smaller capacitance than your estimate
Also, if you refer to question 3 that I asked chat gpt you can see that the discharge time has no bearing on the sum total stored energy.
P = E/t
So yeah, if you calculate for just the duration of the spark time, the wattage number would be decieving, I instead assume that I will capature and condition the power, so for my purposes averaging the current flow into amp-seconds makes more sense and it allows me to present wattage as a smaller and more realistic number.
Here is a great resource where you can quickly calculate the energy stored in a capacitor:
https://www.omnicalculator.com/physics/capacitor-energy
Good work!