There are three ways to shed heat here. Conduction, convection and radiation.
The conduction down the wires would be the main one I think, followed by convection in the air in the bulb and conduction to the glass -(I don't see why it would be a vacuum in the bulb) followed by infrared radiation which would be the smallest heat transfer.
I think this because the LEDs would be running at less than 100 degrees C so radiation losses would be smaller than an incandescent filament bulb where the filament is at 3000 degrees. Also, as mentioned by others in this thread, more successful LED implementations have big conductive heat sinks.
There are three ways to shed heat here. Conduction, convection and radiation.
The conduction down the wires would be the main one I think, followed by convection in the air in the bulb and conduction to the glass -(I don't see why it would be a vacuum in the bulb) followed by infrared radiation which would be the smallest heat transfer.
I think this because the LEDs would be running at less than 100 degrees C so radiation losses would be smaller than an incandescent filament bulb where the filament is at 3000 degrees. Also, as mentioned by others in this thread, more successful LED implementations have big conductive heat sinks.