Again, a fish eye lense will show a curvature where there is none. This film proves nothing.
I am not a flat earther but there are a few facts that disturb me and no one has been able to answer.
Given the curvature of the earth as known or widely accepted, at a 50 miles distance, two ships at sea should have no line of sight contact with each other because each ship would be 1667 feet below the horizon (or seas level) from line of sight contact.
Modern Navy destroyers have laser guided targeting systems that can paint a sea or land target at over 50 miles away for a missile strike at sea level.
If lasers (light rays) do not bend then line of sight targeting should be impossible on an object 1667 foot below line of sight level and yet we paint a laser target with line of site at over 50 miles.
Explain this to me like I am a child, I am listening.
That is what I assumed, but I have it confirmed by both navy and air force personal that they have seen it, even bragged about it but when I asked the same question to them that I did to you good folks, it got them scratching their head.
Their experiences did not include drones or fighters flying out and painting the targets. Just laser targeting from the ships, I even ran the numbers from 200 foot above sea level and the math still does not jive.
As mentioned above, no evidence of a fisheye lens being used, and even such lenses do not show much curvature for things near the centerline of the image.
As for ships and laser pointers, two things to consider: (1) We do not see with straight geometry, because the atmospheric refractive index gradient will cause the light rays to curve slightly and we will see beyond the strict geometric limit. This effect causes the setting or rising sun to be its own disk diameter lower just before geometric sunrise and just after geometric sunset. In radar, this is approximated by the 4/3 Earth rule, but there is still a real horizon, though farther away. (2) If the laser pointer is atop the superstructure, they will see farther anyway. You didn't specify the height above sea level that you are calculating from.
Also, if someone in the superstructure of a ship could see to the horizon 50 miles away. That would be true for someone else in another ship on the opposite side of the horizon. Which means that, superstructure-to-superstructure, they could see each other at a distance of 100 miles. You gotta think about these things.
Maybe it should be stressed more - these cameras are not fisheye lenses, as can clearly be seen by earth curvature panning left to right, across entire view, with zero distortion.
See 12:00 or so and following - left frame has less curvature given first stage separates at lower altitude, but it is quite clear.
Also. Light does bend. Depending on conditions, it curves more or less. The question you would then have to answer is not whether something far away can be seen, but why would it ever not be seen? For example, Chicago skyline can sometimes be seen across Lake Michigan from on top of sand dunes but only the upper parts of the buildings. If flat, why wouldnt the lower halves of the building always be visible with the top halves?
Again, a fish eye lense will show a curvature where there is none. This film proves nothing.
I am not a flat earther but there are a few facts that disturb me and no one has been able to answer.
Given the curvature of the earth as known or widely accepted, at a 50 miles distance, two ships at sea should have no line of sight contact with each other because each ship would be 1667 feet below the horizon (or seas level) from line of sight contact.
https://earthcurvature.com
Modern Navy destroyers have laser guided targeting systems that can paint a sea or land target at over 50 miles away for a missile strike at sea level.
If lasers (light rays) do not bend then line of sight targeting should be impossible on an object 1667 foot below line of sight level and yet we paint a laser target with line of site at over 50 miles.
Explain this to me like I am a child, I am listening.
I'm pretty sure someone closer points the laser.
That is what I assumed, but I have it confirmed by both navy and air force personal that they have seen it, even bragged about it but when I asked the same question to them that I did to you good folks, it got them scratching their head.
Their experiences did not include drones or fighters flying out and painting the targets. Just laser targeting from the ships, I even ran the numbers from 200 foot above sea level and the math still does not jive.
As mentioned above, no evidence of a fisheye lens being used, and even such lenses do not show much curvature for things near the centerline of the image.
As for ships and laser pointers, two things to consider: (1) We do not see with straight geometry, because the atmospheric refractive index gradient will cause the light rays to curve slightly and we will see beyond the strict geometric limit. This effect causes the setting or rising sun to be its own disk diameter lower just before geometric sunrise and just after geometric sunset. In radar, this is approximated by the 4/3 Earth rule, but there is still a real horizon, though farther away. (2) If the laser pointer is atop the superstructure, they will see farther anyway. You didn't specify the height above sea level that you are calculating from.
Also, if someone in the superstructure of a ship could see to the horizon 50 miles away. That would be true for someone else in another ship on the opposite side of the horizon. Which means that, superstructure-to-superstructure, they could see each other at a distance of 100 miles. You gotta think about these things.
Maybe it should be stressed more - these cameras are not fisheye lenses, as can clearly be seen by earth curvature panning left to right, across entire view, with zero distortion.
See 12:00 or so and following - left frame has less curvature given first stage separates at lower altitude, but it is quite clear.
Oh boy, you can repeat it as many times as you like, but there are some here who will never care and keep claiming fish eye
Yes. Those who have no idea how a "fisheye" lens works, and only imagine how it works.
Also. Light does bend. Depending on conditions, it curves more or less. The question you would then have to answer is not whether something far away can be seen, but why would it ever not be seen? For example, Chicago skyline can sometimes be seen across Lake Michigan from on top of sand dunes but only the upper parts of the buildings. If flat, why wouldnt the lower halves of the building always be visible with the top halves?