Your numbers and logic are way off.
180 is the number of educators arrested. Why are you dividing that number by the number of students?
According to the article, 9.6% of students in grades 8 - 11 reported being the victim of sexual misconduct at the hands of an educator.
Grades 8 - 11 represent roughly 4/13 or 31% of the student population (4 years out of 13 years counting k-12). That would represent about 15m students, out of which roughly 1.5m have reported being the victim of sexual misconduct by an educator.
That's just looking at grades 8-11. It certainly doesn't mean k-7 and seniors are any safer.
The horizon does not rise to eye level. Why would you think that it does? If you look straight forward so that your line of sight is level (perpendicular to gravity), then the horizon will fall below that line as you rise in altitude. This is easily observable.
A simple hydrostatic leveling rig can be used to see this. It is a tool for measuring level. Using that one can easily see that at relatively low altitudes (a couple thousand feet), the horizon falls well below level. A bubble level or plumb level could be used as well.
I asked how you explain night and day with a flat Earth model. I noticed you completely avoided answering that.
As for the formula, you asked "can you provide me with the formula for determining the curvature rate of a 25k mile circumference sphere?" I merely provided you with exactly what you asked for.
You asked for an example of how to prove the Earth is spherical. I gave you one. There are many more. I imagine you are going to find them all puzzling though. Here are a couple to think about though.
The visible horizon is further away when we stand at a greater height. If the Earth was flat, that would not be the case. You can see a ship at sea further away if you are atop a tower. Likewise for an island or land mass out at sea. It is the reason sailing ships had crow's nests.
Different parts of the Earth are in day or night at the same point in time. How do you explain that with a flat Earth model?
Gravity pulls us down towards the surface of the Earth. If the Earth was a flat plane of finite size, then as we moved away from the center, there would be larger amount of mass in one direction than in the other. This would result in a gravitational pull towards the center of the finite plane.
And onto your other questions.
Yes, we can just measure the curve.
I do understand spherical geometry. Hence why I pointed out that the formula of 8 inches / mile squared does not model a sphere, it models a parabola.
The formula for determining the curvature rate of a 25k mile circumference sphere is:
height_drop = 3980 * (1 - cos (distance * 0.0145)) Where "height_drop" is the drop in height to the observed object, 3980 is the radius of the 25k mile sphere, "distance" is the distance to the observed object, and 0.0145 is the number of degrees per mile on the surface of a 25k mile sphere.
The point is that you asked: "That means there will be curvature of 8” per mile squared. I ask again, are you able to demonstrate this curvature to me without using NASA as a source?"
And the answer is obviously no - because it is a false assumption about the curvature rate.
Demonstrating the curvature of the Earth is simple in a number of ways. The fact that difference constellations are either visible or not visible from different points on the Earth show that straight up is a different direction from different points on the Earth.
Facebook was down before that post. The first reports of it being down were at 11:30 EST.
That’s what she said